32x-0.8x^2=240

Solution for 32x-0.8x^2=240 equation:

32x-0.8x^2=240

We move all terms to the left:

32x-0.8x^2-(240)=0

a = -0.8; b = 32; c = -240;
Δ = b2-4ac
Δ = 322-4·(-0.8)·(-240)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16}{2*-0.8}=\frac{-48}{-1.6}
=+30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16}{2*-0.8}=\frac{-16}{-1.6}
=+10
$